Note that I did not write this scriptlet this nor do I claim to have written this scriptlet. However, I did want to make sure that I did not lose the link to such a very handy command.

The original can be found here, plus the original article has links to several more useful Urls, so feel free to check it out.

http://cephnotes.ksperis.com/blog/2015/02/23/get-the-number-of-placement-groups-per-osd/

Anyway, now that we got out of the way, here is the script.

[code language=”css”]
ceph pg dump | awk ‘
/^pg_stat/ { col=1; while($col!="up") {col++}; col++ }
/^[0-9a-f]+\.[0-9a-f]+/ { match($0,/^[0-9a-f]+/); pool=substr($0, RSTART, RLENGTH); poollist[pool]=0;
up=$col; i=0; RSTART=0; RLENGTH=0; delete osds; while(match(up,/[0-9]+/)>0) { osds[++i]=substr(up,RSTART,RLENGTH); up = substr(up, RSTART+RLENGTH) }
for(i in osds) {array[osds[i],pool]++; osdlist[osds[i]];}
}
END {
printf("\n");
printf("pool :\t"); for (i in poollist) printf("%s\t",i); printf("| SUM \n");
for (i in poollist) printf("——–"); printf("—————-\n");
for (i in osdlist) { printf("osd.%i\t", i); sum=0;
for (j in poollist) { printf("%i\t", array[i,j]); sum+=array[i,j]; poollist[j]+=array[i,j] }; printf("| %i\n",sum) }
for (i in poollist) printf("——–"); printf("—————-\n");
printf("SUM :\t"); for (i in poollist) printf("%s\t",poollist[i]); printf("|\n");
}’
[/code]

This gives you a nice output as shown below.